Topic: Equalities and Inequalities

Let M be the number of GH¢10 notes and $N$ be the number of GH¢20 notes.

i) The system of linear equations is:

M + N = 273

10M + 20N = 4370

ii) To solve the system, first solve for one variable in terms of the other from the first equation:

M = 273 − N

Substitute $M$ in the second equation:

10 (273 − N) + 20N = 4370

2730 − 10N + 20N = 4370

2730 + 10N = 4370

10N = 4370 − 2730 = 1640

N = 1640/10 = 164

Now substitute N = 164 back into the first equation:

M + 164 = 273 ⇒ M = 273 − 164 = 109

Thus, the number of GH¢10 notes is 109 and the number of GH¢20 notes is 164.